Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
[tex]a=21 \ m , \ b=28 \ m , \ c=5x \ m \\ \\c^2 =a^2 + b^2\\ \\(5x)^2 =21^2 + 28^2\\ \\25x^2=441+784\\ \\25x^2=1225/:25\\ \\x^2=49\\ \\x=\sqrt{49}\\ \\x=7 \ m[/tex]
The value of x of a triangle that has the legs of lengths 28 meters and 21
meters and the hypotenuse of 5x meters is 7
The triangle is a right angle triangle .
Using Pythagoras theorem, let's find the hypotenuse side and invariably the value of x
c² =a² + b²
(5x)² = 28² + 21²
25x² = 784 + 441
25x² = 1225
square root both sides
5x = √1225
5x = 35
divide both sides by 5
5x / 5 = 35 / 5
x = 7
learn more: https://brainly.com/question/3031792?referrer=searchResults
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
