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n is an integer such that 3n + 4 < 19 and
10n/n+ 16 > 1
Find all the possible values of n.


Sagot :

Answer:

Step-by-step explanation:

3n+4<19

3n<19-4

3n<15

n<5

[tex]\frac{10n}{n+16 } >1\\either~ both~ the~ denominator ~ and ~ numerator ~are ~positive ~ or ~both ~are ~ negative.\\let~ 10 n>0 \\n+16 >0\\n>-16\\again ~10 n>n+16\\9n>16\\n>\frac{16}{9} ~...(1)\\and ~\\10n<0,n<0\\and ~n+16 <0\\n<-16\\again\\10n<n+16\\9n<16\\n<\frac{16}{9} \\combining\\n<-16[/tex]

combining

(-∞,-16)U(16/9,5)

Answer:

n = 3,4,5

Step-by-step explanation:

3n + 4 < 19

3n ≤ 15

n ≤ 5

10n/n+16 > 1

10n > n²+16

-n²+10n-16

(-n+2)(n-8)

n = 2 or n = 8

2 < n < 8

So 2<n≤5 = 3,4,5