Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
After 10 years , the number of residents in the community = 100,007.45
Step-by-step explanation:
Let P be the population of a farming community.
As we know that,
Exponential Growth model is :
P(t) = P₀[tex]e^{kt}[/tex] ........(1)
where P₀ is the initial state , k is the growth constant.
As given,
A farming community begins with one resident.
⇒At t = 0 , P(t) = 1
∴ Put t = 0 in equation (1), we get
1 = P₀[tex]e^{0}[/tex]
⇒1 = P₀
∴ equation (1) becomes
P(t) = [tex]e^{kt}[/tex] ......(2)
As given, every year, the number of residents multiplies by 10
⇒At t = 1 , P(t) = 10
∴ Put t = 1 in equation (2), we get
10 = [tex]e^{k}[/tex]
Taking ln both side we get
ln(10) = ln([tex]e^{k}[/tex] )
⇒2.3026 = k
∴ equation (2) becomes
P(t) = [tex]e^{2.3026t }[/tex]
Now, we have to find the population at t = 5
⇒P(5) = [tex]e^{5(2.3026} = e^{11.513} = 100,007.45[/tex]
So, we get
After 10 years , the number of residents in the community = 100,007.45
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.