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Sagot :
Answer:
See explanation
Explanation:
Let us look at the situation closely, the undissociated Hmo is red in colour while the mo^- is yellow in colour.
This means that an acidic solution will appear red while a basic solution will appear yellow in colour.
NaC2H3O2 is a basic salt. When it is introduced, the acetate ion pulls a proton from water forming CH3COOH. CH3COOH is a weak acid and largely does not dissociate, it means that the undissociated acid remains in the solution leaving only the OH^- ions floating around thereby making the solution basic.
The colour of the system now changes to yellow.
Consider the equilibrium;
CH3COO^-(aq) + H2O(l) ------> CH3COOH(aq) + OH^-
Addition of NaC2H3O2 causes the equilibrium of this system to shift to the right.
The methyl orange water equilibrium also shifts towards the position where more mo^-(yellow) is produced.
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