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Sagot :
Answer: 2%
Step-by-step explanation:
Let A be the event of having defective steering and B be the vent of having defective brake linings.
Given: P(A) = 0.03 P(B) = 0.05
P(neither A nor B ) = 0.94
Using formula: P(either A nor B) = 1- P(neither A nor B )
= 1-0.94
i.e. P(either A nor B) =0.06
Using formula:P(A and B) = P(A)+P(B)-P(either A or B)
P(A and B) =0.03+0.05-0.06
= 0.02
Hence, the percentage of the trucks have both defects = 2%
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