Answered

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Find the coordinates of the point on the directed segment from (1,2) to (6,12) that divides it into a ratio of 2:3

Sagot :

Answer:

Point of contact  ( 3,6)

Step-by-step explanation:

Step(i):-

Given that the points are (1,2) and (6,12)

The ratio 2:3 divides the line segment

The line segment divides m:n externally

[tex](\frac{mx_{2}-nx_{1} }{m-n} ,\frac{mx_{2}-nx_{1} }{m-n} )[/tex]

Step(ii):-

(x₁, y₁) = (1,2) and (x₂, y₂)= (6,12) and m:n =2:3

[tex](\frac{2(6)+3(1) }{2+3} ,\frac{2(12)+3(2) }{2+3} )[/tex]

([tex](\frac{12+3}{5} ,\frac{24+6}{5} )[/tex]

([tex]\frac{15}{5} ,\frac{30}{5})[/tex]

(3 , 6)

Final answer:-

Point of contact  ( 3,6)

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