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A, B & C form the vertices of a triangle.

CAB = 90°, ABC = 60° and AB = 8.6.

Calculate the length of BC rounded to 3 SF.

BC =


Sagot :

Answer:

BC = 17.2.

Step-by-step explanation:

Since CAB = 90º, this is a right triangle.

The triangle format is given below:

C

A           B

We have that AB = 8.6, and angle B measures 60º.

Length of BC:

BC is the hypotenyse.

Side AB is adjacent to angle B = 60º.

In a right triangle, angle [tex]\alpha[/tex], it's adjacent side with length s and the hypotenuse h are related by the cosine of the angle, that is:

[tex]\cos{\alpha} = \frac{s}{h}[/tex]

In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So

[tex]\cos{\alpha} = \frac{s}{h}[/tex]

[tex]0.5 = \frac{8.6}{h}[/tex]

[tex]0.5h = 8.6[/tex]

[tex]h = \frac{8.6}{0.5}[/tex]

[tex]h = 17.2[/tex]

BC = 17.2.