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If the fraction of base pairs devoted to protein-coding genes is the same as the fraction of the total genes that they represent, what is the average number of base pairs per protein-coding gene

Sagot :

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[tex]\mathbf{Here \ is \ the \ missing \ part \ of \ the \ question} \\ \\ \mathbf{The \ genome \ of \ Escherichia \ coli \ consists \ of \ 4380 \ genes, \ encoding \ 4290} \\ \\ \mathbf{ proteins, \ in \ jus t \ 5175720 \ base \ pairs. \ What \ percent \ fraction \ of\ the} \\ \\ \mathbf{ Escherichia \ coli \ genes \ encode \ proteins?}[/tex]

Answer:

1182

Explanation:

From the information given:

Number of present genes = 4380

the total no. of protein-encoding =  4290

Total no. of base pairs = 5175720

The percentage fraction of genes encoding the protein is;

total no of protein-encoding gene/total no of present genes

[tex]\mathbf{\dfrac{4290}{4380} = 0.9795}[/tex]

= 97.95%

The average number of base pairs per protein-coding gene is;

= total no. of base-pair/ no of present genes

[tex]\mathbf{ \dfrac{5175720}{4380} = 1181.6} \\ \\ \simeq \mathbf{1182}[/tex]

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