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Find the equation of a straight line which passing through the point (0,-1) which is perpendicular to the line y= -3/4x-3

Sagot :

Answer:

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 2x + 2 is in this form with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

= -  = -  =  

the point (0, 1 ) is the y- intercept ⇒ c = 1

y =  x + 1 ← equation of perpendicular line

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