Answer:
Total distributed load on BE = 5 m²
Explanation:
The first process is to get the value for the Dead load (DL) on the slab;
This is determined by using the formula:
DL = ρ × t
DL = 23.6 kK/m³ × 0.2 m
DL = 4.72 kN/m²
From table 1.4 which relates to the office buildings, we derive the value for the minimum live load (LL) = 2.40 kN/m³
Hence the total load TL = Dead Load DL) + Live loaf (LL)
DL = (4.72 + 2.40) kN/m³
DL = 7.12 kN/m³
Now; from the imaginative view of the information given; the member BE which get the load from half area of the panel BEDC & half the area of BEFA panel parallel to member BE; then the tributary area on member BE can be calculated as;
[tex]A_{BE} = ( \dfrac{a}{2}+\dfrac{a}{2}) \times width[/tex]
[tex]A_{BE} = ( \dfrac{2}{2}+\dfrac{2}{2}) \times 1[/tex]
[tex]A_{BE} =2\times 1[/tex]
[tex]A_{BE} =2 m^2/m[/tex]
The total distributed load acting on BE is:
[tex]Total \ load = TL \times A_{BE}[/tex]
[tex]Total \ load = 7.12 \ \dfrac{kN}{m^2 }\times (2 \times \dfrac{m^2}{m})[/tex]
Total load = 2.5 × 2
Total load = 5 m²
