Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
The answer to the question is
It take for the golf ball hit on Mars to reach the ground 8.284 s longer.
Step-by-step explanation:
To Solve the question, we note that the equation of motion is given to us as
h = -1.9·t² + 26·t
Therefore the height
We compare the above equation with the equation of of motion
S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and - 0.5×g = -1.9
Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²
We now have the time taken to maximum height given by
v = u - g·t where v = 0 at maximum height
We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds
The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s
The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
