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) A 1000-nF capacitor with circular parallel plates with a radius of 1cm is accumulating charge at the rate of 52 mC/s at some point in time. What will be the induced magnetic field strength if you are positioned 20 cm radially outward from the center of the plates

Sagot :

okpalawalter8

Answer:

[tex]B=5.2*10^-^8T[/tex]

Explanation:

From the question we are told that

Capacitor [tex]c=1000nf[/tex]

Radius [tex]r=1cm =>0.001m[/tex]

Charge rate [tex]Q/t=52mC/s[/tex]

Distance [tex]d=20cm =0.2m[/tex]

Generally the rate of charge I is mathematically given as

[tex]I=\frac{dQ}{dt}[/tex]

[tex]I=52Cm/s[/tex]

[tex]I=52*10^-^3C[/tex]

Generally the the magnetic field intensity at distance d is mathematically given as

[tex]B=\frac{\mu I}{2\pi d}[/tex]

[tex]B=\frac{(4 * \pi *10^-^7)(52*10^-^3C)}{2\pi (0.2)}[/tex]

[tex]B=5.2*10^-^8T[/tex]

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