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At a large corporation, 6,000 employees from department A and 4,000 employees from department B are attending a training session. A random sample of 500 employees attending the session will be selected. Consider two sampling methods: with replacement and without replacement. How will the methods affect the standard deviations of the sampling distribution of the sample proportion of employees from department B

Sagot :

Answer:

B: Sampling without replacement will result in a standard deviation less than but close to √0.4(0.6)/500

.Step-by-step explanation:

answer on khan academy

Sampling without replacement will result in the standard deviation greater than but close to [tex]\sqrt{\dfrac{0.4(0.6)}{500}}[/tex] and this can be determined by using the standard deviation formula.

Given :

  • At a large corporation, 6,000 employees from department A and 4,000 employees from department B are attending a training session.
  • A random sample of 500 employees attending the session will be selected.
  • Consider two sampling methods: with replacement and without replacement.

1) With Replacement --

The standard deviation is given by the formula:

[tex]\rm \hat{p}=\sqrt{\dfrac{p(1-p)}{n}}[/tex]          ---- (1)

where the value of 'p' is given by:

[tex]\rm p=\dfrac{4000}{10000}=0.4[/tex]

Now, substitute the value of p and n in the equation (1).

[tex]\rm \hat{p}=\sqrt{\dfrac{0.4(1-0.4)}{500}}[/tex]

[tex]\rm \hat{p}=\sqrt{\dfrac{0.4(0.6)}{500}}=0.02190[/tex]

2) Without Replacement  --

The standard deviation is given by the formula:

[tex]\rm \hat{p}=\sqrt{\dfrac{p(1-p)}{n}\times \left(1-\dfrac{n-1}{N-1}\right)}[/tex]          ---- (2)

where the value 'p' is given by:

[tex]\rm p=\dfrac{4000}{10000}=0.4[/tex]

Now, substitute the value of p, n, and N in equation (2).

[tex]\rm \hat{p}=\sqrt{\dfrac{0.4(1-0.4)}{500}\times \left(1-\dfrac{500-1}{10000-1}\right)}[/tex]

Simplify the above expression.

[tex]\rm \hat{p} = 0.1442[/tex]

So, from the above calculation, the correct option is C) Sampling without replacement will result in the standard deviation greater than but close to [tex]\sqrt{\dfrac{0.4(0.6)}{500}}[/tex].

For more information, refer to the link given below:

https://brainly.com/question/23044118

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