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Sagot :
Question:
find the height of the cylinder whose volume is 1.54 cubic m and radius of the base is 70 cm
Required diagram :
[tex]\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{ 70 \: cm}}\put(9,17.5){\sf{h}}\end{picture}[/tex]
Solution :
For a cylinder having a radius r and a height h ;
Volume Of Cylinder :
- π r² .
Here , the radius of the cylinder is given as 70 cm and the volume is 1.54 m³ .
Converting ;
- 1 m³ = 1 × 10⁶ cm³ .
- > 1.54 × 10⁶ cm³ .
- > 1540000 cm ³.
- > π r² h = 1540000
- > 22/7 × 70 × 70 × h = 1540000
- > 22 × 10 × 70 h = 1540000
- > 15400 h = 1540000
- > h = 100 cm = 1 m.
The height of the cylinder is 100cm.=1m.
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