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9. If the perimeter of an isosceles triangle is 83 cm. and its base is 23 cm. Find the measure of its equal sides.


10. The perimeter of a rhombus is 5.6 cm. Find its side.


11. The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of the
rectangle is 26 m. What is its breadth ?


12. What is the cost of fencing a rectangular field of length 16 m and breadth 11 m at the rate of 12 per m.

Please solve all questions..step by step.​

Sagot :

lucky75

Required Answers :-

9.

Q:-If the perimeter of an isosceles triangle is 83 cm. and its base is 23 cm. Find the measure of its equal sides.

Answer:- As we know that Perimeter is the sum of all sides.

  • Let the both side be x
  • 83 = 23 + (x + x)
  • 83 - 23 = 2x
  • 60 = 2x
  • 30 = x

Other two sides are 30 cm.

10.The perimeter of a rhombus is 5.6 cm. Find its side.

Answer:- As we know that

Side of Rhombus = Perimeter/4

  • Side = 5.6/4
  • Side = 1.4 cm
  • Side is 1.4 cm

11.The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of the

The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of therectangle is 26 m. What is its breadth ?

Answer:- Perimeter of square = 4 × s

  • Perimeter = 4 × 17
  • Perimeter = 68 cm

Now,

  • Perimeter of rectangle = 2(l + b)
  • 68 = 2(26 + b)
  • 68/2 = 26 + b
  • 34 = 26 + b
  • 34 - 26 = b
  • 8 = b
  • b=8

12.What is the cost of fencing a rectangular field of length 16 m and breadth 11 m at the rate of 12 per m.

Answer:- Perimeter = 2(l + b)

  • Perimeter = 2(16 + 11)
  • Perimeter = 2(27)
  • Perimeter = 54 cm

Now,

  • Total cost = 54 × 12
  • Total cost = ₹648.

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