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Sagot :
Answer:
Pulled and wattled = 9/16
Pulled and no wattle = 3/16
horned and wattled = 3/16
horned and no wattle = 1/16
Explanation:
Pulled = P, Horned = p
Wattled = W, no wattle = w
Polled, wattle goats = P_W_
Since they produced offspring with horns and no wattles (ppww), it means both parents have the recessive allele for each trait. Hence, they are both heterozygotes with PpWw as genotypes.
PpWw x PpWw
Genotypes ratio of the offspring:
P_W_ - 9/16
P_ww - 3/16
ppW_ - 3/16
ppww - 1/16
Phenotype ratio of the offspring:
Pulled and wattled = 9/16
Pulled and no wattle = 3/16
horned and wattled = 3/16
horned and no wattle = 1/16
(See the attached image for the Punnet's square)
Some alleles of a gene are dominant to others masking the effect this other alleles.
The polled, or no horn, trait (P) is dominant to the horned (p) trait.
Having wattles (W) is dominant to not having wattles (w).
A breeder crosses a polled, wattled male goat with a polled, wattled female goat.
The phenotypic and genotypic ratios would be
- Polled and wattled = P_W_ = 9/16
- Polled with no wattle = P_ww = 3/16
- horned and wattled = ppW_ = 3/16
- horned with no wattle = pwpw = 1/16
Parent genotype --- polled, wattled male and female goat -- P_W_
As the cross produced offspring with horns and no wattles (ppww), it shows both parents have the recessive allele for each trait.
Hence, they are both heterozygotes with PpWw for the traits.
Parent genotypes: PpWw x PpWw
PW Pw pW pw PW Pw pW pw
PW Pw pW pw
PW PPWW PPWw PpWW PpWw
Pw PPWw PPww PpWw Ppww
pW PpWW PpWw ppWW ppWw
pw PpWw Ppww ppWw ppww
Learn more:https://brainly.com/question/23796622
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