Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A car is traveling at 35.8 m/s. What acceleration would it have if it took 2.0 s to come to a complete stop?

Sagot :

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf a= -17.9 \ m/s^2}}[/tex]

Explanation:

Acceleration is equal to the change in velocity over the change in time.

[tex]a=\frac{v_f-v_i}{t}[/tex]

The initial velocity is 35.8 meters per second. The final velocity is 0 meters per second when the car comes to a complete stop. The time is 2.0 seconds.

[tex]v_f= 0 \ m/s \\v_i= 35.8 \ m/s \\t= 2 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{0 \ m/s - 35.8 \ m/s }{2 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{ -35.8 \ m/s} {2 \ s}[/tex]

Divide.

[tex]a= -17.9 \ m/s/s = -17.9 \ m/s^2[/tex]

The car's acceleration is -17.9 meters per square second. The acceleration is negative because the car was coming to a stop and slowing down.

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.