Answered

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Write the standard form of the equation of the circle below.
Center (0,-1) passes through the point (-1,-2)

Sagot :

mberisso

Answer:

[tex]x^2+(y+1)^2=2[/tex]

Step-by-step explanation:

We use the formula for a circle with center at (0, -1), that goes through the (x, y) point (-1, -2):

[tex](x-0)^2 + (y-(-1))^2 = R^2\\Using \,\,\,point\,\,\,(-1, -2)\\(-1-0)^2+ (-2+1)^2 = 1 + 1 = 2 = R^2[/tex]

Therefore, the equation of this circle can be written as:

[tex]x^2+(y+1)^2=2[/tex]

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