ln(40) + 2ln(1/2) + ln(x)
First, you should take the 2 and put it back in the argument. Since it's a coefficient, when you put it back it in would be a power. That changes 2ln(1/2) to ln(1/2 ^ 2), which is ln(1/4).
ln(40) + ln(1/4) + ln(x)
Then, to add these, we just multiply the arguments, meaning we just have:
ln(40 * 1/4 * x)
Multiply and then we're done.
ln(10x)
Using logarithmic function, the condense of Ln 40 + 2 ln 1/2 + ln x is ln(10x).
Logarithmic function is function is an " inverse of an exponential function so that the independent variable appears logarithmic function".
According to question,
Ln 40 + 2 ln 1/2 + ln x
Properties of Logarithmic function [tex]x ln (a) = ln(a^x)[/tex].
Using above properties we can write [tex]2 ln \frac{1}{2}[/tex] [tex]= ln(a^(\frac{1}{2})^2)[/tex] [tex]=ln(a^\frac{1}{4})[/tex].
Properties of Logarithmic function [tex]ln(a) + ln(b) = ln(ab)[/tex]
Using above properties we can write Ln 40 + 2 ln 1/2 + ln x as [tex]ln(40 . \frac{1}{4}.x)[/tex].
= [tex]ln(10x)[/tex]
Hence, Using logarithmic function, the condense of Ln 40 + 2 ln 1/2 + ln x is ln(10x).
Learn more about Logarithmic function here
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