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Sagot :
(Pi value = 3)
Given diameter of circle = 12 inches
Radius of circle :
[tex] = \tt\frac{diameter}{2} [/tex]
[tex] = \tt\frac{12}{2} [/tex]
[tex] = \tt6 \: inches[/tex]
Thus, the radius of this circle = 6 inches
Circumference of this circle :
[tex] = \tt2\pi r[/tex]
[tex] =\tt 2 \times 3 \times 6[/tex]
[tex] = \tt36 \: inches[/tex]
Thus, the circumference of this circle = 36 inches
The area of this circle :
[tex] = \tt\pi {r}^{2} [/tex]
[tex] =\tt 3 \times 6 \times 6[/tex]
[tex] = \tt108 \: {inches}^{2} [/tex]
Thus, the area of this circle = 108 inches²
Therefore,
Radius = 6 inches
Diameter = 12 inches
Circumference = 36 inches
Area = 108 inches²
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