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A line that includes the points (-9,-5) and (-10, j) has a slope of -10. What is the value of J

Sagot :

Answer:

j = -15

Step-by-step explanation:

Given that,

A line that includes the points (-9,-5) and (-10, j) has a slope of -10.

The slope of a line for which two points are given is :

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}\\\\-10=\dfrac{j-(-5)}{-10-(-9)}\\\\10=\dfrac{j+5}{-10+9}\\\\10=\dfrac{j+5}{-1}\\\\-10=j+5\\\\j=-10-5\\\\j=-15[/tex]

So, the value of j is equal to -15.

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