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Factor each expression, if possible. Identify any special cases, such as the difference of squares or a perfect square trinomial xy-4y+2x-8

Sagot :

Answer:

[tex]xy-4y+2x-8 = (y + 2)(x-4)[/tex]

Step-by-step explanation:

Given

[tex]xy-4y+2x-8[/tex]

Required

Factor the expression

[tex]xy-4y+2x-8[/tex]

Group the expression

[tex](xy-4y)+(2x-8)[/tex]

Factor each group

[tex]y(x-4)+2(x-4)[/tex]

This gives:

[tex](y + 2)(x-4)[/tex]

Hence:

[tex]xy-4y+2x-8 = (y + 2)(x-4)[/tex]