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Consider this system of linear equations;
y=-3x + 5
y= mx + b
Which values of m and b will create a system of linear equations with no solution?
m = -3 and b = -3
m = 5 and b = -3
m = 3 and b = 5
m = -3 and b = 5

Sagot :

xero099

Answer:

The values of [tex]m_{2}[/tex] and [tex]b_{2}[/tex] that will create a system of linear equations with no solution are [tex]m_{2} = -3[/tex] and [tex]b_{2} = -3[/tex].

Step-by-step explanation:

An example of a system of linear equations are two lines parallel to each other. In other words, there are two lines such that:

[tex]y = m_{1}\cdot x + b_{1}[/tex] (1)

[tex]y = m_{2}\cdot x + b_{2}[/tex] (2)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]m_{1}[/tex], [tex]m_{2}[/tex] - Slope.

[tex]b_{1}[/tex], [tex]b_{2}[/tex] - y-Intercept.

If both lines are parallel to each other, then we must observe these two conditions:

1) [tex]m_{1} = m_{2}[/tex]

2) [tex]b_{1} \ne b_{2}[/tex]

Therefore, the values of [tex]m_{2}[/tex] and [tex]b_{2}[/tex] that will create a system of linear equations with no solution are [tex]m_{2} = -3[/tex] and [tex]b_{2} = -3[/tex].

View image xero099

Answer:

(A) m = -3 and b = -3

Step-by-step explanation:

EDG 2021

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