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Answer:

[tex]\frac{x^3 +7x^2-2x-6}{x+ 7} \ = \ x^2 -2 \ +\ \frac{8}{x^3 +7x^2-2x-6}[/tex]

Step-by-step explanation:

Given polynomial function;

x³ + 7x² - 2x - 6

divisor of the polynomial = x + 7

The function is divided as follows;

                                   x²  - 2

                               ---------------------------

                  x + 7   √ x³ + 7x² - 2x - 6

                              - (x³  + 7x²)      ↓

                              -----------------------------

                                                 -2x - 6

                                               - (-2x - 14)

                               -----------------------------------

                                                           8

Since there is a remainder of 8, then the result is expressed as follows; [tex]q(x) + \frac{r(x)}{b(x)} = x^2 -2 \ +\ \frac{8}{x^3 +7x^2-2x-6}[/tex]

                       

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