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Sagot :
Answer:
[tex]Given,\\y = 4x+1......(1)\\y = 2x^2+7x-1.............(2)\\Equating~equation (1)~and~(2),\\4x+1 = 2x^{2} +7x-1\\or, 2x^{2}+7x-4x-1-1=0\\or, 2x^{2} + 3x-2=0\\or, 2x^{2} +4x-x-2=0\\or, 2x(x+2)-1(x+2)=0\\or, (x+2)(2x-1)=0\\i.e. x=-2 ~or~ \frac{1}{2} \\When~x=2,~equation(1)~becomes ~y=4(-2) +1=-7\\When~x=-\frac{1}{2},~equation (1)~becomes~y=4(\frac{1}{2}) +1 = 2+1=3[/tex]
So, the required values of x are -2 and 1/2 and that of y are -7 and 3.
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