Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:
[tex]P(Tail = 1) = \frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]Flips = 2[/tex]
Required
Probability of exactly one tail
This event can be represented as:
(Head and Tail) or (Tail and Head)
In the flip of a coin (penny), the following probabilities exist:
[tex]P(Head) = \frac{1}{2}[/tex]
[tex]P(Tail) = \frac{1}{2}[/tex]
So, the required probability is:
[tex]P(Tail = 1) = (P(Head) * P(Tail)) + (P(Tail) * P(Head))[/tex]
Substitute values for P(Head) and P(Tail)
[tex]P(Tail = 1) = (\frac{1}{2}*\frac{1}{2}) + (\frac{1}{2}*\frac{1}{2})[/tex]
[tex]P(Tail = 1) = (\frac{1}{4}) + (\frac{1}{4})[/tex]
[tex]P(Tail = 1) = \frac{1}{4} + \frac{1}{4}[/tex]
Take LCM
[tex]P(Tail = 1) = \frac{1+1}{4}[/tex]
[tex]P(Tail = 1) = \frac{2}{4}[/tex]
[tex]P(Tail = 1) = \frac{1}{2}[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.