niaritchmon
Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

usebthe elimination method to solve the following system of equations
4x+y=13
5x-y=5​

Usebthe Elimination Method To Solve The Following System Of Equations4xy135xy5 class=

Sagot :

Answer:

x = -2, y = 21

Step-by-step explanation:

Let 4x + y = 13 to be equation1 {eqn1}

and let 5x - y = 5 to be equation2 {eqn2}

Using elimination method, you would try to make sure a particular unknown has the same value in both equation 1 and 2. This would make it easy for you to subtract one equation from the other.

Notice how the value of y is the same in both equations. That's a good sign.

But the signs aren't the same. Meaning y in eqn1 has a value of +1, and y in eqn2 has a value of -1. We need to make them similar.

So, we multiply the value of y in eqn1 by all the terms in eqn2. And, do pretty much the same thing by multiplying the value of y in eqn2 by all the terms in eqn1.

You would have:

-1 * (4x + y = 13)

+1 * (5x - y = 5)

This would result in;

-4x -  y = -13 (eqn3)

5x - y = 5 (eqn4)

So, just subtract eqn3 from 4

You would have;

(5x - -4x) + (-y -- y) = (-13 - 5)

9x + 0 = -18

x = -18/9 = -2

and to find y;

just substitute the value of x into any of the 4 equations. let's try equation 1

Therefore;

4(-2) + y = 13

-8 + y = 13

y = 13 + 8 = 21

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.