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In the coordinate plane, quadrilateral ABCD has vertices A(-2, 3), B(4,5), C(10, -1), and D(8, -9). Let E, F, G, and H
be the midpoints of AB, BC, CD, and DA, respectively.
Prove that quadriateral EFGH is a parallelogram.
Enter your proof in the space provided.​


Sagot :

Answer:

 G(3, 1), H(2, 3)

Step-by-step explanation:

When D is the midpoint of EG, it means ...

 D = (E + G)/2

or

 G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)

Likewise, H is ...

 H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)

not my answer but i hope it helps you.

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