Trippytaro
Answered

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You apply a force of 500 N to 150 N/m. how much does it stretch? Show the equation you are using, plus the values into the equation, and show the final answer with the units. 3 significant figures.

Sagot :

quasarJose

Answer:

3.33m

Explanation:

Given parameters:

Force applied  =500N

Elastic constant  = 150N/m

Unknown:

Amount of stretch or extension  = ?

Solution:

To solve this problem use the expression below:

    F  = k e

F is the force applied

k is the elastic constant

e is the extension

  So;

           500  = 150 x e

             e  = [tex]\frac{500}{150}[/tex]    = 3.33m

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