Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

3. How many grams of oxygen are needed for the
complete combustion of 11 grams of propane, C3H8?
C3H8 + 5 O2 + 3 CO2 + 4 H2O

Sagot :

Neetoo

Answer:

Mass = 40 g

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of propane = 11 g

Solution:

Chemical equation:

C₃H₈ +5O₂   →     3CO₂ + 4H₂O

Number of moles of propane:

Number of moles = mass/molar mass

Number of moles = 11 g/ 44.1 g/mol

Number of moles = 0.25 mol

now we will compare the moles of propane and oxygen.

              C₃H₈        :          O₂

                  1           :            5

                0.25      :            5/1×0.25 = 1.25 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.25 mol × 32 g/mol

Mass = 40 g

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.