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3. A sample of neon gas has a volume of 1.2 L at 28.5°C. What will the volume be at 125°C it the
pressure remains constant?


Sagot :

Answer:

1.58L

Explanation:

Given parameters:

Initial volume  = 1.2L

Initial temperature  = 28.5°C  = 28.5 + 273  = 301.5K

Final temperature  = 125°C  = 125 + 273  = 398K

Unknown:

New volume  = ?

Solution:

Volume and temperature relationship is resolved using the Charles's law.

The law states that "the volume of a fixed mass of a gas varies directly as its absolute temperature if the the pressure is constant".

So;

       [tex]\frac{V1}{T1}[/tex]    = [tex]\frac{V2}{T2}[/tex]  

V1 is the initial volume

T1 is the initial temperature

V2 is the new volume

T2 is the new temperature

             [tex]\frac{1.2}{301.5}[/tex]    = [tex]\frac{V2}{398}[/tex]    

              301.5V2  = 477.6

                       V2  = 1.58L

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