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Sagot :
Answer:
x=12, y=4
Step-by-step explanation:
All the sides are the same length.
3x+y = 40
4x-2y = 40
Eliminate y terms: divide second equation by 2 and add to first equation
2x-y = 20
3x+y = 40
---------------
5x = 60
x = 12
y = 40-3x = 4
Answer:
We know that all sides of the equilateral triangle is equal.
Given :---
An equilateral triangle has a side length of 40.
Another side of the same triangle measures
3x + y.
The third side of the same triangle measures
4x - 2y.
According to the above problem, the equation are
3x+y=40........(i) and 4x-2y=40.........(ii)
Divide the equation (ii) by 2, we get
2x-y=20..........(iii)
Now solving for x and y we get,
3x+y=40.......(i)
2x-y=20........(iii)
5x =60
x=60/5
x=12
Putting the value of x in equation in equation (iii) we get
24-y=20
y=24-20
y=4
The values of x and y that would keep the triangle equilateral are 12 and 4 respectively.
Hence, the value of x is 12 and y is 4.
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