likesomenewromantic
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

115 mL of a 2.35 M potassium
fluoride (KF) solution is diluted with 1.28 L of water. What is the new concentration in molarity?
? M KF

Sagot :

ardni313

The new concentration : = 0.194 M

Further explanation

Given

115 mL(0.115 L) of a 2.35 M Potassium  fluoride (KF)

1.28 L of water

Required

The new concentration

Solution

Dilution is the process of adding solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂  

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = volume of the solution after dilution

V₂=0.115 + 1.28 = 1.395 L

Input the value :

M₂ = (M₁V₁)/V₂

M₂ = (2.35 x 0.115)/1.395

M₂ = 0.194

Answer: 0.194

Explanation:

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.