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how to distribute this problem:
(x-8)^2 + 16

Sagot :

absor201

Answer:

We conclude that:

[tex]\left(x-8\right)^2+16=x^2-16x+80[/tex]

Step-by-step explanation:

Given the equation

[tex]\left(x-8\right)^2\:+\:16[/tex]

First, solve (x - 8)²

Apply Perfect Square formula:    (a - b)² = a² - 2ab + b²

[tex]a=x,\:\:b=8[/tex]

[tex]\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2[/tex]

             [tex]=x^2-16x+64[/tex]

so the expression becomes

[tex]\left(x-8\right)^2+16=x^2-16x+64+16[/tex]

                     [tex]=x^2-16x+80[/tex]           Add the numbers: 64+16=80

Therefore, we conclude that:

[tex]\left(x-8\right)^2+16=x^2-16x+80[/tex]

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