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If a child applies a 3.00 N force for 2.00 m in the same direction the car is already moving, how much work is done on the car?

Sagot :

Answer:

W = 6 J

Explanation:

Given that,

The force acting on the car, F = 3 N

Displacement in the car, d = 2 m

We need to find the work is done on the car. The work done by the car is given by the relation as follows :

[tex]W=Fd\\\\W=3\ N\times 2\ m\\\\W=6\ J[/tex]

So, 6 J of work is done on the car.