Willow1987
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-4y + 7 = 35y - 6
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Answer:

[tex]y=\frac{1}{3}[/tex]

Step-by-step explanation:

Subtract [tex]7[/tex] from both sides of the equation:

[tex]-4y+7=35y-6[/tex]

[tex]-4y+7[/tex][tex]-7=35y-6[/tex][tex]-7[/tex]

Simplify:

  • Subtract the numbers:

[tex]-4y+7[/tex][tex]-7=35y-6-7[/tex]

[tex]-4y=35y-6-7[/tex]

  • Subtract the numbers:

[tex]-4y=35y[/tex][tex]-6[/tex][tex]-7[/tex]

[tex]-4=35y[/tex][tex]-13[/tex]

[tex]-4y=35y-13[/tex]

Subtract [tex]35y[/tex] from both sides of the equation:

[tex]-4y=35y-13[/tex]

[tex]-4y[/tex][tex]-35y=35y-13[/tex][tex]-35y[/tex]

Simplify:

  • Combine like terms:

[tex]-4[/tex][tex]-35y=35y-13-35y[/tex]

[tex]-39y=35y-13-35y[/tex]

  • Combine like terms:

[tex]-39y=35y-13[/tex][tex]-35y[/tex]

[tex]-39y=-13[/tex]

[tex]-39y=-13[/tex]

Divide both sides of the equation by the same term:

[tex]-39y=-13[/tex]

[tex]\frac{-39y}{-39} =\frac{-13}{-39}[/tex]

Simplify:

  • Cancel terms that are in both the numerator and denominator:

[tex]\frac{-39y}{-39} =\frac{-13}{-39}[/tex]

[tex]y=\frac{-13}{-39}[/tex]

  • Divide the numbers:

[tex]y=\frac{-13}{-39}[/tex]

[tex]y=\frac{1}{3}[/tex]

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