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how to factor 8x^2+17x-4

Sagot :

Answer:

8x^2+17x-4 = 1/16 (16x + 17 - √417) (16x + 17 + √417)

Step-by-step explanation:

ax²+bx+c=0

roots: x = (-b±√b²-4ac) / 2a   ... a=8   b=17   c=-4

roots: (-17±√17²-4*8*(-4)) / (2*8) = (-17±√17²-4*8*(-4)) / (2*8)

= (-17±√417) / 16

8x^2+17x-4 = (x - (-17+√417) / 16) (x - (-17-√417) / 16)

                  = 1/16 (16x + 17 - √417) (16x + 17 + √417)

                   

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