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Calculate the mass defect of Ti-48 (atomic mass = 47.947947 amu)

Proton: 1.00783 amu

Neutron: 1.00866 amu


Sagot :

Answer: 0.449

Explanation:

Ti48

Z=22

22 protons, 26 neutrons

22*1.00783 + 26*1.00866 = 48.397 - 47.947947 = 0.449

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