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A baseball (m = 140 g) traveling at 30. m/s moves a fielder's glove backward 35 cm when the ball is caught.  
What was the average force exerted by the ball on the glove?​

Sagot :

evgeniylevi

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

[tex]F=\frac{mV^2}{2L};[/tex]

4) according to the last formula

[tex]F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).[/tex]

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