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A car is moving along Highway 138 according to the given equation, where x meters is the directed distance of the car from a given point P at t hours. Find the values of t for which the acceleration is zero, and then find the position of the car at this time.

x = 1/4t^3 + 1/6t^3 - t^2+ 1

Sagot :

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Answer:

1111¹5&-78+&%%567;!9098888

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