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A figure skater begins spinning counterclock-
wise at an angular speed of 4.6 7 rad/s. Dur-
ing a 4.2 s interval, she slowly pulls her arms
inward and finally spins at 7.3 7 rad/s.
What is her average angular acceleration
during this time interval?
Answer in units of rad/s.​


Sagot :

Answer:

Angular acceleration, [tex]\alpha =0.64\ rad/s^2[/tex]

Explanation:

Given that,

Initial angular velocity, [tex]\omega_i=4.67\ rad/s[/tex]

The final angular velocity, [tex]\omega_f=7.37\ rad/s[/tex]

Time, t = 4.2 s

We need to find her average angular acceleration  during this time interval. Acceleration is the rate of change of velocity. So,

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{7.37-4.67}{4.2}\\\\\alpha =0.64\ rad/s^2[/tex]

So, her average angular acceleration is [tex]0.64\ rad/s^2[/tex].

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