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Sagot :

Answer:

x = 4 and y = 1

Step-by-step explanation:

The given equations are :

2x+5y = 13 ...(1)

3x-2y = 10 ...(2)

The elimination method is appropriate to solve the given system of equations.

Multiply equation (1) by 3 and equation (2) by 2.

6x+15y=39 ...(3)

6x-4y=20 ...(4)

Subtract equation (3) from (4).

6x-4y-(6x+15y) = 20-39

6x-4y-6x-15y = -19

-19y=-19

y = 1

Put the value of y in equation (1).

2x+5y = 13

2x+5=13

2x=8

x = 4

So, the solution of the given equations are x = 4 and y = 1.

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