alewis34
Answered

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In ΔHIJ, i = 9.2 cm, j = 1.4 cm and ∠H=84°. Find the length of h, to the nearest 10th of a centimeter

Sagot :

Answer:

9.2

Step-by-step explanation:

S.A.S.→Law of Cosines

a^2=b^2+c^2-2bc\cos A

From reference sheet.

h^2 = 9.2^2+1.4^2-2(9.2)(1.4)\cos 84

=84.64+1.96−2(9.2)(1.4)(0.104528)

Square and find cosine.

h^2 = 84.64+1.96-2.69265

h  

2

=84.64+1.96−2.69265

Multiply.

h^2 = 83.90735

h  

2

=83.90735

Add.  

h=  

83.90735

​  

≈9.16≈9.2

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