Answered

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6 Which element requires the least amount of
energy to remove the most loosely held electron
from a gaseous atom in the ground state?
(1) Na
(3) P
(2) Ar
(4) Ci

Sagot :

Answer: 1) Na because it requires least amount of energy.

Tutorconsortium330

Na requires the least amount of energy to remove the most loosely held electron.

Why does Na have the least ionization enthalpy among the given elements?

Electronic configuration of the elements:

Na - [Ne] 3s¹

P - [Ne] 3s² 3p³

Ar - [Ne] 3s² 3p⁶

Cl - [Ne] 3s² 3p⁵

  • As it can be seen, Na after losing one electron from its outermost subshell attains a stable noble gas configuration. So, it will require a very less amount of energy i.e., ionization enthalpy, to remove that electron.

  • P, which already has a half-filled subshell, will not readily lose the electrons and hence requires more amount of energy.

  • Ar has the noble gas configuration i.e., all its subshells are fully filled. A very large amount of energy will be required to remove its electron.

Learn more about ionization energy here:

https://brainly.com/question/27938503?referrer=searchResults

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