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Find the values of a and b such that
x^2 + 3x + 4 = (x + a)^2+ b


Sagot :

bok333

Answer:

[tex]x {}^{2} + 3x + 4 = (x + a) {}^{2} + b \\ x {}^{2} + 3x + 4 = x {}^{2} + 2ax + a {}^{2} + b \\ = x {}^{2} + a {}^{2} + 2ax + b \\ 2a = 3 \\ b = 4 \\ a = \frac{3}{2} \\ b = 4[/tex]

Answer:

a=3/2

b=7/4

hope this help