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How do you solve 2x^2 - 7x -5= 0 in quadratic form?

Sagot :

stuperkins

Answer:

Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...

2x2 + 7x = -3

2x2 + 7x + 3 = 0

Once the equation is in standard form, factor the quadratic expression.

2x2 + 7x + 3 = 0

(2x + 1)(x + 3) = 0

Using the Zero Product Property set each factor equal to 0 and solve for x.

2x + 1 = 0  

2x + 1 - 1 = 0 - 1 x + 3 = 0

2x = -1 x + 3 - 3 = 0 - 3

2x 2 = -1 2 x = -3

x = -1 2  

The solutions to the equation are -1 2 and -3.

Answer:

x^1 = 7-square root89/4

x^2 = 7+square root89/4

Step-by-step explanation:

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