Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

How do you solve 2x^2 - 7x -5= 0 in quadratic form?

Sagot :

stuperkins

Answer:

Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...

2x2 + 7x = -3

2x2 + 7x + 3 = 0

Once the equation is in standard form, factor the quadratic expression.

2x2 + 7x + 3 = 0

(2x + 1)(x + 3) = 0

Using the Zero Product Property set each factor equal to 0 and solve for x.

2x + 1 = 0  

2x + 1 - 1 = 0 - 1 x + 3 = 0

2x = -1 x + 3 - 3 = 0 - 3

2x 2 = -1 2 x = -3

x = -1 2  

The solutions to the equation are -1 2 and -3.

Answer:

x^1 = 7-square root89/4

x^2 = 7+square root89/4

Step-by-step explanation:

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.