Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

How much heat is absorbed when a 298.3 g piece of brass goes from 30.0 to150 degrees Celsius? The specific heat of brass is .038 J/goC. PLEASE HELP

Sagot :

Neetoo

Answer:  

Heat absorbed = 1360.248 j  

Explanation:  

Given data:  

Mass of brass = 298.3 g  

Initial temperature = 30.0°C  

Final temperature = 150°C  

Specific heat capacity of brass = 0.038 J/g.°C  

Heat absorbed = ?  

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:  

Q = m.c. ΔT  

Q = amount of heat absorbed or released  

m = mass of given substance  

c = specific heat capacity of substance  

ΔT = change in temperature  

ΔT = 150°C - 30.0°C    

ΔT = 120°C  

Q = 298.3 g × 0.038 J/g.°C × 120°C  

Q = 1360.248 j

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.