Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How much heat is absorbed when a 298.3 g piece of brass goes from 30.0 to150 degrees Celsius? The specific heat of brass is .038 J/goC. PLEASE HELP

Sagot :

Neetoo

Answer:  

Heat absorbed = 1360.248 j  

Explanation:  

Given data:  

Mass of brass = 298.3 g  

Initial temperature = 30.0°C  

Final temperature = 150°C  

Specific heat capacity of brass = 0.038 J/g.°C  

Heat absorbed = ?  

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:  

Q = m.c. ΔT  

Q = amount of heat absorbed or released  

m = mass of given substance  

c = specific heat capacity of substance  

ΔT = change in temperature  

ΔT = 150°C - 30.0°C    

ΔT = 120°C  

Q = 298.3 g × 0.038 J/g.°C × 120°C  

Q = 1360.248 j

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.