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a boy runs a distance of 10m in 2secound and walks further a distance of 8m in 3secound,what is his overage speed?​

Sagot :

Answer:

3.6m/s

Explanation:

To solve this problem, we must find the total distance and the total time taken. We then plug it into the equation defined below:

Average speed  = [tex]\frac{total distance}{total time taken}[/tex]  

 Total distance  = 10m + 8m  = 18m

  Total time taken  = 2s + 3s  = 5s

So;

 Average speed  = [tex]\frac{18}{5}[/tex]    = 3.6m/s