Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
By Newton's second law, the gravitational force F between an object of mass m and a planet of radius r and mass M is on the surface of the planet is
F = G M m / r ² = m a
where
G = 6.67 × 10⁻¹¹ N•m²/kg², the universal gravitational constant
a = the acceleration of the object (not the planet; note that the right side is m times a, and not M times a)
The object's mass cancels on either side, leaving you with
a = G M / r ²
and this acceleration is due to gravity. On Earth, a = g.
Let M be the mass of Earth and r its radius; then
g (Earth) = G M / r ² ≈ 9.80 m/s²
To find g on Mercury, replace r with 0.38r and M with 0.055M :
g (Mercury) = G (0.055M) / (0.38r )² = 0.055/0.38² G M / r ²
g (Mercury) ≈ 0.38 g (Earth) ≈ 3.73 m/s²
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.