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given: BD is a diameter

m 1 = 100°
m BC = 30°
m AC =

60
110
200


Given BD Is A Diameter M 1 100 M BC 30 M AC 60 110 200 class=

Sagot :

Answer:

110°

Step-by-step explanation:

[tex] m\angle 1 + m\angle 2 = 180\degree [/tex]

(linear pair angles)

[tex] 100\degree + m\angle 2 = 180\degree [/tex]

[tex] m\angle 2 = 180\degree- 100\degree [/tex]

[tex] m\angle 2 = 80\degree [/tex]

[tex] \because m\widehat {AB} =m\angle 2 [/tex]

(Measure of the minor arc is equal to the corresponding central angle)

[tex] \therefore m\widehat {AB} = 80\degree [/tex]

[tex] \because m\widehat {AC} =m\widehat {AB} +m\widehat {BC}[/tex]

(By arc sum property)

[tex] \therefore m\widehat {AC} = 80\degree+30\degree [/tex]

[tex] \huge \red {\boxed {\therefore m\widehat {AC} = 110\degree}} [/tex]